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112+12v-4v^2=0
a = -4; b = 12; c = +112;
Δ = b2-4ac
Δ = 122-4·(-4)·112
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-44}{2*-4}=\frac{-56}{-8} =+7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+44}{2*-4}=\frac{32}{-8} =-4 $
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